The length of a rectangle is 7 yd more than twice the width, and the area of the rectangle is 99 yds squared. Find the dimensions of the rectangle.

L is 7 more than twice W

L=7+2W

area ia 99

99=LW

sub 7+2W for L

99 = (7+2W) W

99=7W+2W^2

minus 99 from both sides

0=2W^2+7W-99

factor

0 = (W+9) (2W-11)

set each to zero

W+9=0

W=-9

fasle, measurement cannot be negative

2W-11=0

add 11

2W=11

divide 2

W=5.5

the width is 5.5

sub

L=7+2W

L=7+2 (5.5)

L=7+11

L=18

the dimentions is 18yd by 5.5 yd