A bag has ten marbles in it. Three of them are green one of them is red four of them are yellow and two of them are blue. If one marble is taken out of the bag randomly what is the probability that it will neither be green nor yellow?

A 0.40

B 0.30

C 0.30 or 0.40

D 0.70

Question

Malcolm Lam

Mathematics

10 April, 10:51

A bag has ten marbles in it. Three of them are green one of them is red four of them are yellow and two of them are blue. If one marble is taken out of the bag randomly what is the probability that it will neither be green nor yellow?

A 0.40

B 0.30

C 0.30 or 0.40

D 0.70

+4

Answers (2)

Know the Answer?

Santino · Answer 1

Since there's 3 green and 4 yellow that adds up to 7 and with only 3 marbles left that is 3:10 and that make the probability 30% or 0.30

Darrell Hatfield · Answer 2

B is correct.

Step-by-step explanation:

3+4=7

10-7 is the probability of neither Green or Yellow, so 10-7=3.

3/10 is 0.30 in decimal notation, so b is correct.

A bag has ten marbles in it. Three of them are green one of them is red four of them are yellow and two of them are blue. If one marble is taken out of the bag randomly what is the probability that it will neither be green nor yellow?A 0.40B 0.30C 0.30 or 0.40D 0.70

A bag has ten marbles in it. Three of them are green one of them is red four of them are yellow and two of them are blue. If one marble is taken out of the bag randomly what is the probability that it will neither be green nor yellow?

A 0.40

B 0.30

C 0.30 or 0.40

D 0.70