How do u write 6 more the 7 times a number is 41 in algebraic equation?

Question

Sheppard

Mathematics

31 January, 18:58

How do u write 6 more the 7 times a number is 41 in algebraic equation?

+1

Answers (2)

Know the Answer?

Peter · Answer 1

First you have to give the number a name. Call it Bob.

6 more than 7 times Bob is 41.

(7 Bob) + 6 = 41

Garrett · Answer 2

Let the number be y.

7 times the number means 7y.

therefore, 6 more than 7y is 41 means

6 + 7y = 41.

Further simplification:

6 + 7y = 41

7y = 41 - 6 = 35

y = 35/7

= 5