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13 March, 06:54

Find the 7th term of the arithmetic sequence - 5x-8,-x-14,3x-20, ...

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  1. 13 March, 07:01
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    A₁ = - 5x-8; a₂ = - x-14; a₇=?

    d = a₂ - a₁

    = x-14 - (-5x-8)

    = - x - 14 + 5x + 8

    = 4x-6

    a (n) = a₁ + (n-1) d

    a₇ = - 5x-8 + (7-1) (4x-6)

    = - 5x-8 + 6 (4x-6)

    = - 5x - 8 + 24x - 36

    = 19x - 44
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