If a bridge is 1,053 feet above the Arkansas river, about how long will it take before the stone hits the water?

Assuming air resistance is negligible and a constant gravitational field.

h (t) = 1053-16t^2 So the stone will hit the water when h (t) = 0 so

1053-16t^2=0

16t^2=1053

t^2=65.8125, since t>0

t≈8.1 seconds (to nearest tenth of a second)