4^2-6 (2^x) - 16=0

solve for x

Assuming that 4^2-6 (2^x) - 16=0 is correct, we can rearrange it as:

-6 (2^x) + 4^2 - 16=0

Are you sure it's not 6 (2^x) + 4^2 - 16=0?

If 6 (2^x) + 4^2 - 16=0 is correct, then

6 (2^x) + 4^2 - 16=16 - 16 = 0, that is, 6 (2^x) = 0. Then x = 0 (answer)