Christov and Mateus gave out candy to children on Halloween. They each have out candy at a constant rate, and they both gave away all of their candy. Christov initially had 300 pieces of candy, and after he was visited by 17 children, he had 249 pieces left. The number of remaining pieces of candy Mateus had as function of the number of children who visited him is given by the following function: C (n) = 270-3n. Who gave more candy to each child who visited him? Who gave candy to a greater number of children?

Answer: 1) Both gave same number of candies to each child.

2) Christov gave candy to a greater number of children.

Step-by-step explanation:

Since, Christov initially had 300 pieces of candy, and after he was visited by 17 children, he had 249 pieces left.

Let he gave x candy to each student when he visited 17 children.

Then, 17 x + 249 = 300

⇒ 17 x = 51

⇒ x = 3

Since, he distributes candies in a constant speed.

Therefore, his speed of distribution = 3 candies per child

Now, The function that shows the remaining number of candies Mateus has after distributing candies to n children,

C (n) = 270 - 3 n

Initially, n = 0

C (0) = 270

⇒ Mateus has initial number of candies = 270

When he gave candies to one child then remaining candies = 270 - 3 * 1 = 267

Thus, the candies, get by a child from Mateus = 270 - 267 = 3

Since, he distributes candies in a constant speed.

⇒ His speed of distribution = 3 candies per child

1) Therefore, Both Christov and Mateus have same speed of distribution.

2) Since, both have same seed.

⇒ The one who has greater number of candies will be distribute more.

⇒ Christov will give more candies.