Given the list of terms 1/3 , 1, 5/3, 7/3, ... Find the 15th and - 16th term.

15th term = 29/3

16th term = 31/3

Step-by-step explanation:

Given an arithmetic sequence with the first term a1 and the common difference d, the nth (or general) term is given by an=a1 + (n-1) d.

First we find the 15th term

n=15

a1=1/3

d=1 - 1/3 = 2/3

Solution

1/3 + (15-1) 2/3

1/3+28/3

(1+28) / 3

29/3

Lets find the 16th term

1/3 + (16-1) 2/3

1/3+30/3

(1+30) / 3

31/3