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Rene Fisher
Mathematics
15 November, 11:39
Solve using integrating factor (x^5+3y) dx-xdy=0
tnx
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Gabriel Mitchell
15 November, 11:55
0
(x^5 + 3y) dx - xdy = 0
x^5 + 3y - xdy/dx = 0
3y - xdy/dx = - x^5
dy/dx - 3/x y = x^4
I. F. = e^∫ (-3/x) = 1/x^3
(dy/dx) / x^3 - (3/x) y/x^3 = x^4/x^3
(dy/dx) / x^3 - 3/x^4 y = x
(1/x^3 y) ' = x
∫ (1/x^3 y) 'dx = xdx
1/x^3 y = 1/2 x^2 + c
y = (x^5) / 2 + cx^3
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