About 38% of people who get their eyes examined are found to be farsighted (unable to see objects close-up). What is the probability of an ophthalmologist examining six people until he finds the first patient who is farsighted? (0.62) 5 (0.38) 1 (0.38) 6 (0.38) 5 (0.62) 1 (0.62) 6 1 - (0.38) 5

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Beasley

Mathematics

Today, 04:56

About 38% of people who get their eyes examined are found to be farsighted (unable to see objects close-up). What is the probability of an ophthalmologist examining six people until he finds the first patient who is farsighted? (0.62) 5 (0.38) 1 (0.38) 6 (0.38) 5 (0.62) 1 (0.62) 6 1 - (0.38) 5

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Martin · Answer 1

1) Probability of not getting a patient with farsightedness = 1-0.38 = 0 ... 62.

Probability of examining 6 patients until a patient with farsightedness is examined = The Probability that the first six patients do not have farsightedness = 0.62*0.62*0.62*0.62*0.62*0.62 = 0.626. So option 4 is the correct answer.

1 - (0.38) 5