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Zara Coffey
Mathematics
10 May, 21:11
Solving system of equations by substitution
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Tyson
10 May, 21:33
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Y=3x-10 and 3x+2y=16
y=3x-10
subsitute 3x-10 for y in other equation
3x+2y=16
3x+2 (3x-10) = 16
distribute
3x+6x-20=16
9x-20=16
add 20 both sides
9x=36
divide both sides by 9
x=4
sub back
y=3x-10
y=3 (4) - 10
y=12-10
y=2
x=4
y=2
(4,2) is soluiton
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