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10 May, 21:11

Solving system of equations by substitution

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  1. 10 May, 21:33
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    Y=3x-10 and 3x+2y=16

    y=3x-10

    subsitute 3x-10 for y in other equation

    3x+2y=16

    3x+2 (3x-10) = 16

    distribute

    3x+6x-20=16

    9x-20=16

    add 20 both sides

    9x=36

    divide both sides by 9

    x=4

    sub back

    y=3x-10

    y=3 (4) - 10

    y=12-10

    y=2

    x=4

    y=2

    (4,2) is soluiton
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