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16 May, 04:09

What is the completely factored form of 3x^5-7x^4+6x^2-14x?

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  1. 16 May, 04:28
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    x (x - 7) (x^3 + 2)

    Step-by-step explanation:

    Note that x is a common factor here:

    3x^5-7x^4+6x^2-14x = x (3x^4 - 7x^3 + 6x - 14), or:

    x (3x^4 - 7x^3 + 6x - 14) Note that 6x - 14 can be rewritten as 2[x - 7]

    and that 3x^4 - 7x^3 can be rewritten as x^3[x - 7]

    Therefore, x (3x^4 - 7x^3 + 6x - 14 becomes:

    x (x - 7) (x^3 + 2)
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