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17 December, 19:58

If x^2 + xy = 20 and dx/dt = - 4 when x = - 5 and y = 1, what is dy/dt

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  1. 17 December, 20:25
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    3.2

    Step-by-step explanation:

    x² + xy = 20

    Take the derivative with respect to time:

    2x dx/dt + x dy/dt + y dx/dt = 20

    (2x + y) dx/dt + x dy/dt = 20

    Given x = - 5, y = 1, and dx/dt = - 4:

    (2 (-5) + 1) (-4) + (-5) dy/dt = 20

    (-10 + 1) (-4) - 5 dy/dt = 20

    36 - 5 dy/dt = 20

    5 dy/dt = 16

    dy/dt = 3.2
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