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11 February, 23:06

Whlch set of numbers contains both solutions to the equation x2 - 2x - 8 = 0?

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  1. 11 February, 23:27
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    Answer: x = {-2, 4}

    Step-by-step explanation:

    0 = x² - 2x - 8



    1 - 8 = - 7

    2 - 4 = - 2 This works because the b-value is - 2!

    0 = (x + 2) (x - 4)

    0 = x + 2 0 = x - 4

    x = - 2 x = 4
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