What is value of 3x2+4y2if x=2, y=1, and z=-3

0 if the original expression is : 3x^2 + 4yz

Step-by-step explanation:

3x^2 + 4yz; I guess this is the original expression.

When x=2, y = 1 z = -3

3x^2 + 4yz = 3 (2) ^2 + 4 * (1) * (-3)

= 3*4 + 4 * (-3) = 12 - 12 = 0

16

Step-by-step explanation:

3x² + 4y² where x = 2, y = 1, and z = - 3

Here we just need to plug in the given values to their respective variables

3 (2) ² + 4 (1) ² There are no z variables in this equation so plugging in z = - 3 is irrelevant Simplifying our equation we now have: 3 (4) + 4 (1) = 12 + 4 = 16