Three times Andy's age is eleven more than twice belinda's age. the sum of their ages is two less than twice belinda's age. how old is each person

A=andy's age

b=belinda's age

3a=11+2b

a+b=-2+2b

wowie

a+b=-2+2b

minus b from both sides

a=b-2

subsitute b-2 for a

3a=11+2b

3 (b-2) = 11+2b

3b-6=11+2b

minus 2b from both sides

b-6=11

add 6 to both sides

b=17

subsitute

a=b-2

a=17-2

a=15

andy is 15

belinda is 17