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28 July, 03:16

If the side of the square is (4x-2y) what is the perimeter of the square

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  1. 28 July, 03:18
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    The perimeter of a square is a^2. In this case a = (4x-2y) so a^2 = (4x-2y) ^2, a^2={16 (x) ^2-16xy+4 (y) ^2}
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