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6 December, 21:03

Find four consecutive even integers such that the sum of twice the first, five times the second, and four times the third divided by three the fourth equals 3.

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  1. 6 December, 21:29
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    2x + 5 (x + 2) + 4 (x + 4) / 3 (x + 6) = 3

    11x + 26 / 3x + 18 = 3

    11x + 26 = 9x + 54

    2x = 28

    x = 14

    The integers are 14, 16, 18 and 20 Answer
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