When 4 times a number is increased by 6, the result is 58, what is the number?

Well you can start by making an equation

4 times a number. we'll call "a number" B

so it would be 4B

increased by 6 is + 6

so we have 4B+6

results in 58 would be = 58

your equation is 4B+6=58

subtract 6 from both sides to isolate the variable

4B+6=58

-6 - 6

4B=52 then divide by 4 to get B alone

:4 : 4

B=13

so the number in the problem is 13