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28 December, 18:40

What is (x-2) ^5 in pascels triangle

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  1. 28 December, 18:55
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    (x-2) ^5 = x^5 + 5x^4 * 2 + 10x^3 * 2^2 + 10x^2 * 2^3 + 5x * 2^4 + 2^5

    simplify:

    (x-2) ^5 = x^5 + 10x^4 + 40x^3 + 80x^2 + 80x + 32
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