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Adonis
Mathematics
28 December, 18:40
What is (x-2) ^5 in pascels triangle
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Mueller
28 December, 18:55
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(x-2) ^5 = x^5 + 5x^4 * 2 + 10x^3 * 2^2 + 10x^2 * 2^3 + 5x * 2^4 + 2^5
simplify:
(x-2) ^5 = x^5 + 10x^4 + 40x^3 + 80x^2 + 80x + 32
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