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Stitch
Mathematics
31 March, 10:54
What are the real numbers for x^2-3x+8=0
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Mr. Clean
31 March, 11:19
0
Has no real solution (only imaginary solutions)
Step-by-step explanation:
x²-3x+8=0
recall for a quadratic equation in the form
ax² + bx + c = 0
the if b² - 4ac is negative (i. e less than zero), then the equation has no real solutions.
in this case,
a=1, b = - 3 and c=8
b² - 4ac,
= (-3) ² - (4) (1) (8)
= 9 - 32
= - 23 (negative number hence no real solutions)
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