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23 August, 09:35

Find two consecutive even integers such that twice the smaller is 16 more than the larger.

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  1. 23 August, 09:40
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    Answer: smaller: 18; larger: 20

    Step-by-step explanation:

    Let n be the smaller integer. Then the larger integer is n+2. So:

    2n=n+2+16

    n=18

    The smaller integer is 18; the larger one is 20.
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