David rented a truck for one day. There was a base fee of 17.95, and there was an additional charge of 91 cents for each mile driven. David has to pay 188.12 when he returned the truck. For how many miles did he drive the truck

Question

Jack Russell

Mathematics

18 December, 13:13

David rented a truck for one day. There was a base fee of 17.95, and there was an additional charge of 91 cents for each mile driven. David has to pay 188.12 when he returned the truck. For how many miles did he drive the truck

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Cordell Acevedo · Answer 1

Ok so you need an equation. 188.12 is the total cost he ends up paying. 17.95 is the base fee/y-intercept and the $0.91 for each mile driven is the slope. So, the equation will be like this: (total cost) = (slope) + (base fee) Now let's plug in the numbers. 188.12=0.91x+17.95. Now we solve for x. (X represents the number of miles driven.

188.12=0.91x+17.95 (first subtract 17.95 from both sides of the equation) (after this you get 170.17=0.91x. (Now divide by 0.91 on both sides)