What is the first step in writing f (x) = 3x2 + 6x - 8 in vertex form?

A. Factor out 3 from each term.

B. Form a perfect square trinomial by keeping the value of the C. function equivalent.

D. Write the trinomial as a binomial squared.

E. Factor out 3 from the first two terms.

Question

Karly Frey

Mathematics

31 December, 10:49

What is the first step in writing f (x) = 3x2 + 6x - 8 in vertex form?

A. Factor out 3 from each term.

B. Form a perfect square trinomial by keeping the value of the C. function equivalent.

D. Write the trinomial as a binomial squared.

E. Factor out 3 from the first two terms.

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Answers (1)

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Cedric Lambert · Answer 1

The first step in writing f (x) = 3x² + 6x - 8 in vertex form is

E. Factor out 3 from the first two terms.

f (x) = 3x² + 6x - 8

f (x) = 3 (x² + 2x) - 8

f (x) + 8 = 3 (x² + 2x + __)

f (x) + 8 + 1 = 3 (x² + 2x + 1)

f (x) + 9 = 3 (x+1) ²

f (x) = 3 (x+1) ² - 9

What is the first step in writing f (x) = 3x2 + 6x - 8 in vertex form?A. Factor out 3 from each term.B. Form a perfect square trinomial by keeping the value of the C. function equivalent.D. Write the trinomial as a binomial squared.E. Factor out 3 from the first two terms.

What is the first step in writing f (x) = 3x2 + 6x - 8 in vertex form?

A. Factor out 3 from each term.

B. Form a perfect square trinomial by keeping the value of the C. function equivalent.

D. Write the trinomial as a binomial squared.

E. Factor out 3 from the first two terms.