use the intermediate value theorem to determine, if possible, whether g (x) = 2x^3+3x^2-3x+4 has a real zero between - 2 and - 1

Step-by-step explanation:

g (-2) = 2 (-2) ^3+3 (-2) ^2-3 (-2) + 4=-16+12+6+4=6

g (-1) = 2 (-1) ^3+3 (-1) ^2-3 (-1) + 4=-2+3+3+4=8

it does not change sign, so there is no real zero between - 2 and - 1.