Find the equation of the line through ( - 7, - 2) that is perpendicular to the line y = x/3 + 6.

y+3x+23=0

Step-by-step explanation:

From y = x/3 + 6 comparing with general equation of a line, y = mx + c

m1 = 1/3

Perpendicularity rule states that m1m2 = - 1

m2 = - 1/1/3 = - 1 * 3/1 = - 3

The equation is

y-y1 = m2 (x-x1)

y - (-2) = - 3 (x - (-7))

y+2 = - 3 (x+7)

y+2 = - 3x-21

y = - 3x-21-2

y = - 3x-23

y+3x = - 23

y+3x+23=0