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31 October, 05:40

Find the difference. (2x^2 - 3x + 7) - (x^2 + 6x - 12) A)

A) x^2 + 3x - 5

B) x^2 - 3x + 19

C) x^2 - 6x + 12

D) x^2 - 9x + 19

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Answers (1)
  1. 31 October, 05:58
    0
    Its D.

    (2x^2 - 3x + 7) - (x^2 + 6x - 12)

    Distribute the negative over the second parentheses:-

    = (2x^2 - 3x + 7) - x^2 - 6x + 12

    = x^2 - 9x + 19 (answer)
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