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2 July, 22:58

Prove that - -

sec^2ø-tan^2ø=1

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  1. 2 July, 23:20
    0
    Step-by-step explanation:

    We know that sin²Ф+cos²Ф=1

    when you divide both sides by cos²Ф you get

    sin²Ф/cos²Ф+cos²Ф/cos²Ф=1/cos²²Ф

    sin²Ф/cos²Ф=tan²Ф

    cos²Ф/cos²Ф=1

    1/cos²Ф=sec²Ф

    tan²Ф+1=sec²Ф

    subtract tan²Ф on both sides

    1=sec²Ф-tan²Ф

    therefore sec²Ф-tan²Ф=1
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