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Vicente
Mathematics
8 June, 13:07
Solve for the interval 2sin (2x) = 1
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Nola Serrano
8 June, 13:30
0
Hello:
2sin (2x) = 1
sin (2x) = 1/2
sin (2x) = sin (π/6)
(2x = π/6 + 2kπ) or (2x = π-π/6 + 2k π) ... k in Z
(x = π/12 + kπ) or (x = 5π/12 + kπ)
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