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25 January, 09:26

What is the polar form of the equation? x^2 + (y+5) ^2=25

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  1. 25 January, 09:32
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    x=√-y^2-10y

    Step-by-step explanation:

    step 1:add y^-2 to both sides

    x^2 + (y+5) ^2=25

    x^2+y^2+10y+25+-y^2=25+-y^2

    x^2+10y+25=-y^2+25

    Step 2:add - 10y to both sides

    x^2+10y+25-10y=-y^2+25+-10y

    x^2+25=-y^2-10y+25

    step 3:add - 25 to both sides

    x^2+25-25=y^2-10y+25-25

    x^2=-y^2-10y

    step 4:take square root

    x=√-y^2-10y
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