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19 August, 20:18

11. A carousel has a diameter of 50 feet. To the nearest foot, how far does a child

seated near the outer edge travel when the carousel makes 8

revolutions?

+3
Answers (2)
  1. 19 August, 20:23
    0
    1257 ft.

    50 x 3.14 = 157.1

    8 x 157.1 = 1257
  2. 19 August, 20:27
    0
    1256 ft

    Step-by-step explanation:

    The circumference of a circle tell us how long is the line which enclose the circle. So, after 1 revolution a child seated near the outer edge travels a distance equal to the circumference of the carousel. If 8 revolutions are made the distance travelled will be 8 times the circumference.

    Circumference = π · diameter = π · 50 ft = 157 ft

    Distance travelled = 8 · 157 ft = 1256 ft
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Home » Mathematics » 11. A carousel has a diameter of 50 feet. To the nearest foot, how far does a child seated near the outer edge travel when the carousel makes 8 revolutions?
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