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What is the probability that a poker hand contains exactly one pair (that is, a poker hand with exactly four different ranks) ?

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  1. 1 June, 08:38
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    The probability is

    (13 4) (4 2) (4^4) / (52 5)

    =715*6*256 / 2598960

    =0.423 (correct to the nearest 3 decimal places)
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