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6 July, 01:19

Tina is 7 times older than her daughter Aisha and the sum of their ages is 48, find their current ages.

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Answers (2)
  1. 6 July, 01:22
    0
    let the present age of daughter be X

    then the age of tina will be 7X

    Step-by-step explanation:

    the sum of their ages = 48

    7x+x=48

    8x=48

    x=48/8

    x=6

    the age of daughter is 6yrs

    the age of tina 7x=7*6=42yrs
  2. 6 July, 01:36
    0
    Aisha is 6 years old and Tina is 42 years.

    Step-by-step explanation:

    Let Tina's age be = 7Q

    Let Aisha's age be = Q

    Then,

    7Q + Q = 48

    8Q = 48

    Q = 48/8

    Q = 6

    Therefore Aisha's age is 6 years old

    Tina's age is 7 * 6 = 42
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