Find the equation in terms of x of the line through (-3,1) and (3,0)

The answer to your question is: y = - 1/6 x + 1/2

Step-by-step explanation:

Data

A (-3, 1)

B (3, 0)

Formula

m = (y2 - y1) / (x2 - x1)

y = mx + b

(y - y1) = m (x - x1)

Process

m = (0 - 1) / (3 + 3)

m = - 1 / 6

(y - 1) = - 1/6 (x + 3)

6 (y - 1) = - 1 (x + 3)

6y - 6 = - x - 3

6y = - x - 3 + 6

6y = - x + 3

y = - 1/6 x + 3/6

y = - 1/6 x + 1/2

x + 6y - 3 = 0

x = - 6y + 3