A box is dragged 16 m across a level floor by a 25-N force at an angle of 45° to the floor. It is then dragged by

the same force 7 m up a ramp inclined at an angle of 10° to the floor. Determine the total work done by the

force.

Question

Darwin Bolton

Mathematics

7 October, 20:13

A box is dragged 16 m across a level floor by a 25-N force at an angle of 45° to the floor. It is then dragged by

the same force 7 m up a ramp inclined at an angle of 10° to the floor. Determine the total work done by the

force.

+1

Answers (1)

Know the Answer?

Travis Lowe · Answer 1

solution

W=f*d*cos theta

=25N*16m*cos 45°

=400Nm*cos 45°

=282.84J

W=f*d*cos theta

=25N*7m*cos 10°

=175Nm*cos10°

=172.34J

Total workdone=282.84J+172.34J=455.18J

A box is dragged 16 m across a level floor by a 25-N force at an angle of 45° to the floor. It is then dragged bythe same force 7 m up a ramp inclined at an angle of 10° to the floor. Determine the total work done by theforce.

A box is dragged 16 m across a level floor by a 25-N force at an angle of 45° to the floor. It is then dragged by

the same force 7 m up a ramp inclined at an angle of 10° to the floor. Determine the total work done by the

force.