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2 July, 15:00

Write a polynomial function of least degree with integral coefficients that has the given zeros of 5 and - 2i

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  1. 2 July, 15:22
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    Hello:

    f (x) = (x-5) (x+2i)

    = x² + 2ix - 5x-10i

    f (x) = x² + (2i-5) x - 10i

    coefficients : a = 1 b = 2i-5 c = - 10i
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