The sum of three consecutive even integers is 162 as an algebraic equation?

F (x) = x + (x+1) + (x+2)

162 = x + (x+2) + (x+4)

Solve for x and x will be equal to the first integer

Solved:

162 = x + (x+2) + (x+4)

162 = 3x + 6

156 = 3x

52 = x

The consecutive integers will be 52, 54, 56