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21 February, 21:12

For a convex 40-gon, what is the sum of the measures of the interior angles?

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  1. 21 February, 21:28
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    The sum of the measures of a polygon's interior angles will always be:

    (n - 2) 180° where n is the number of sides/angles.

    Plug 40 in for n:

    angle sum = (n - 2) 180

    sum = (40 - 2) 180

    sum = 38 * 180 = 6840

    Thus, the sum of the interior measures of a 40-gon is 6840°.
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