Jan's Age is 3 years less than twice Tritts age. The sum of their ages is 30. Find their ages.

Question

Abraham Richards

Mathematics

28 February, 15:32

Jan's Age is 3 years less than twice Tritts age. The sum of their ages is 30. Find their ages.

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Answers (2)

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Elaina Reese · Answer 1

J + t = 30

j = 2t - 3

now we sub

(2t - 3) + t = 30

3t - 3 = 30

3t = 30 + 3

3t = 33

t = 33/3

t = 11 < = = Tritt's age

j = 2t - 3

j = 2 (11) - 3

j = 22 - 3

j = 19 < = = Jan's age

Areli Arellano · Answer 2

2x-3+x=30

3x-3=30

3x=33

Tritts age=x=11

Jans age=2x-3=2 (11) - 3=22-3=19

Tritt=11

Jan=19