Your cousin, who is planning her wedding, is working on the seating chart for the reception. She is trying to decide which 6 people should be seated at the table closest to the head table. She has narrowed her decision down to a list of 10 friends.

If the order doesn't matter, in how many ways can she choose 6 friends from the list of 10 to sit at the table closest to the head table?

Question

Gunnar Frank

Mathematics

7 September, 19:54

Your cousin, who is planning her wedding, is working on the seating chart for the reception. She is trying to decide which 6 people should be seated at the table closest to the head table. She has narrowed her decision down to a list of 10 friends.

If the order doesn't matter, in how many ways can she choose 6 friends from the list of 10 to sit at the table closest to the head table?

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Answers (1)

Know the Answer?

Lorenzo Ochoa · Answer 1

Final list of friends = 10

Possible number of friends who can sit close to the head table = 6

This is a question of the number of combinations in choosing 6 friends from the list of 10 friends.

That is,

Number of ways = 10C6 = (10!) / [6! * (10-6) !] = 3628800 / (720*24) = 210 ways.