What are the exact solutions of x^2 = 4 - 7x? x = x equals negative 7 plus or minus the square root of thirty-three all over 2 x = x equals negative 7 plus or minus the square root of sixty-five all over 2 x = x equals 7 plus or minus the square root of sixty-five all over 2 x = x equals 7 plus or minus the square root of thirty-three all over 2

Question

Jagger Horn

Mathematics

31 July, 16:59

What are the exact solutions of x^2 = 4 - 7x? x = x equals negative 7 plus or minus the square root of thirty-three all over 2 x = x equals negative 7 plus or minus the square root of sixty-five all over 2 x = x equals 7 plus or minus the square root of sixty-five all over 2 x = x equals 7 plus or minus the square root of thirty-three all over 2

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Answers (1)

Know the Answer?

Pierce Bailey · Answer 1

x² = - 7x + 4

x² + 7x - 4 = 0

x = - 7 ± √ (7² - 4 (1) (-4))

2 (1)

x = - 7 ± √ (49 + 16)

2

x = - 7 ± √ (65)

2

x ≈ - 7 ± 8.06

2

x ≈ - 3.5 ± 4.03

x ≈ - 3.5 + 4.03 or x ≈ - 3.5 - 4.03

x ≈ 0.53 or x ≈ - 7.53