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25 July, 19:21

What is the remainder when x^2-5x-22 is divided by x+3?

I'd also like to know how to do it so I can do the rest on my own and make sure I'm doing It right

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  1. 25 July, 19:41
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    First, you need to find the zero of x+3, which is - 3

    then you multiply - 3*1, which equals - 3

    the reason why I multiplied - 3*1 is because the 1 is the coefficient of x^2 but we just don't see it because we don't need to.

    once we get - 3 we add that to the next coefficient (-5)

    -3+-5=-8

    we take the sum (-8) and multiply that to - 3 (the zero of x+3)

    we get 24, so we add - 22+24=2

    -22 Is the next coefficient to come and 2 is our remainder

    the new equation is: x-8 remainder 2
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