Determine the amounts of 20% and 50% salt solutions that should be mixed to obtain 300 gallons of 41% salt solution.

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Question

Hallie Le

Mathematics

18 July, 12:12

Determine the amounts of 20% and 50% salt solutions that should be mixed to obtain 300 gallons of 41% salt solution.

Will give brainliest to best answer

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Answers (1)

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Abram Knox · Answer 1

Assume that solution with 20% and 50% salt is x and y gallons respectively.

Therefore,

x+y = 300 = > y=300-x

Additionally

20x+50y = 300*41 = 12300

Substituting for y

20x+50 (300-x) = 12300 = > 20x+15000-50x = 123000 = > - 30x = - 2700

x = 90 gallons

y = 300-x = 300 - 90 = 210 gallons

Determine the amounts of 20% and 50% salt solutions that should be mixed to obtain 300 gallons of 41% salt solution.Will give brainliest to best answer

Determine the amounts of 20% and 50% salt solutions that should be mixed to obtain 300 gallons of 41% salt solution.

Will give brainliest to best answer