Mike discovered that the pool in his backyard is leaking slowly. The pool holds 16,307 gallons of water, and is leaking at a rate of 4 gallons per day. If Mike does not replace the water that has leaked from the pool, how many gallons of water will remain in the pool after 192 days?

Question

Doran

Mathematics

31 March, 23:55

Mike discovered that the pool in his backyard is leaking slowly. The pool holds 16,307 gallons of water, and is leaking at a rate of 4 gallons per day. If Mike does not replace the water that has leaked from the pool, how many gallons of water will remain in the pool after 192 days?

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Answers (2)

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Jacqueline Wang · Answer 1

15,539 gallons

Step-by-step explanation:

16,307 - 4x = y;

16,307 - 4 (192) = y;

4 x 192 = 768;

16,307 - 768 = 15,539

Taylor Bullock · Answer 2

15,539 gallons will remain after 192 days

Step-by-step explanation:

16,307 - 4x = y

Plug in 192 for x since that's how many days will have passed.

16,307 - 4 (192) = y

4 x 192 = 768

Then, subtract 768 from 16,307 to see how many gallons will remain.

16,307 - 768 = 15,539