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28 November, 03:03

Find three consecutive integers whose sum is 9 greater than twice the largest integer

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  1. 28 November, 03:12
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    Ur 3 consecutive integers : x, x + 1, x + 2

    x + x + 1 + x + 2 = 2 (x + 2) + 9

    3x + 3 = 2x + 4 + 9

    3x + 3 = 2x + 13

    3x - 2x = 13 - 3

    x = 10

    x + 1 = 10 + 1 = 11

    x + 2 = 10 + 2 = 12
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