Cindy has a jar of mixed nuts. There are two pecans, three peanuts, and one cashew in the jar. Cindy grabs two nuts and gives them to her friend, Paul, and he eats them. What is the probability of Paul eating a cashew and a pecan?

A 1/18

B 1/15

C 2/11

D 1/4

Question

Kaylie

Mathematics

25 August, 01:32

Cindy has a jar of mixed nuts. There are two pecans, three peanuts, and one cashew in the jar. Cindy grabs two nuts and gives them to her friend, Paul, and he eats them. What is the probability of Paul eating a cashew and a pecan?

A 1/18

B 1/15

C 2/11

D 1/4

+3

Answers (1)

Know the Answer?

Hugh Palmer · Answer 1

B 1/15

Step-by-step explanation:

This is non-replacement choosing, so no matter which order is that (cashew-pecan or pecan-cashew) the probability is either

1 / 6 x 2 / 5 or 2 / 6 x 1 / 5 = 2/30 = 1/15

Cindy has a jar of mixed nuts. There are two pecans, three peanuts, and one cashew in the jar. Cindy grabs two nuts and gives them to her friend, Paul, and he eats them. What is the probability of Paul eating a cashew and a pecan?A 1/18B 1/15C 2/11D 1/4

Cindy has a jar of mixed nuts. There are two pecans, three peanuts, and one cashew in the jar. Cindy grabs two nuts and gives them to her friend, Paul, and he eats them. What is the probability of Paul eating a cashew and a pecan?

A 1/18

B 1/15

C 2/11

D 1/4