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20 March, 13:20

Solve 3^ (2x) = 7^ (x_1).

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Answers (2)
  1. 20 March, 13:22
    0
    x=1 - log9 log7 = - 0.12915, nearly.
  2. 20 March, 13:36
    0
    Applying log to both sides of equation, we get:

    2x log 3 = (x-1) log 7

    x=-0.12915
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