Ask Question
11 January, 11:13

Find the partial sum of the first 100 terms of the series 4,8,12,16.

+3
Answers (1)
  1. 11 January, 11:14
    0
    Hello:

    16-12=12-8=8-4=4 ... (common diff by arithmetic sequence)

    a1 = 4

    an = a1 + (n-1) r ... r = 4

    a100 = a1 + (100-1) * 4 = 4+99*4 = 5*99 = 495

    the partial sum of the first 100 terms is : S100

    S100 = 100/2 (4+495) = 24950
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find the partial sum of the first 100 terms of the series 4,8,12,16. ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers