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Isabela Luna
Mathematics
4 November, 06:18
How do you factor tan^2x-3tanx-2
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Julius Erickson
4 November, 06:25
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Let tanx = y or just use it as a variable
tan^2x - 3tanx - 2
a = 1, b = - 3, c = - 3
quadratic formula
tanx = [-b + sqrt (b^2 - 4 ac) ] / 2 a
= [ 3 + sqrt (9 + 12) ] / 2 = 3.56
tanx = [-b - sqrt (b^2 - 4 ac) ] / 2 a
= [ 3 - sqrt (9 + 12) ] / 2 = - 0.56
x = 1st or 3rd quadrant
x = tan^-1 (3.56) = 74.3 (1st)
x = 180 + 74.3 (3rd)
x = tan^-1 (-0.56) two options either 2nd quarter or 4th quadrant
x = 180 - 29.2 (2nd)
x = 360 - 29.2 (4th)
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