Which is the solution for log (4x-1) = log (x+1) + log2?

x = 1.5

Step-by-step explanation:

Solution

log (4x - 1) - log (x+1) = log2 log (x + 1) was subtracted from both sides log[ (4x - 1) / log (x+1) ] = log2 Subtaction of logs means division (4x - 1) / (x + 1) = 2 Take the antilog of both sides 4x - 1 = 2 (x + 1) Remove the brackets 4x - 1 = 2x + 2 Add 1 to both sides 4x = 2x + 3 Subtract 2x 4x - 2x = 3 2x = 3 Divide by 2 x = 3/2 Answer

Check

Left Hand Side

log (4*1.5 - 1) log (6 - 1) log (5)

Right Hand Side

log (1.5 + 1) + log (2) log (2.5) + log (2) log2*2.5 log 5

And they check

It's x=3/2

Step-by-step explanation:

Took it just now